If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2-11x-32=0
a = 3; b = -11; c = -32;
Δ = b2-4ac
Δ = -112-4·3·(-32)
Δ = 505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{505}}{2*3}=\frac{11-\sqrt{505}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{505}}{2*3}=\frac{11+\sqrt{505}}{6} $
| K=-2(7+2k) | | -6w+4(w+8)=12 | | -x×14=-5x+54 | | (3•x-48)•(x-8)=0 | | 36/n=9 | | X^2-130*x-900=0 | | 9+3a-4=3a-20+15 | | 3/4x+15/10=2/8x | | 2t^2-8t-42=0 | | 9^(2x-1)=36^(x) | | y-3=5-3y | | 22x-3^2-7=0 | | 9(y-1)=54 | | 8x-1=3x+14 | | 10x^2-43x+12=0 | | 7-8x-12x^2=0 | | (12-4x)/(2x+5)=0 | | 9-(3x-1)^2=0 | | 15x-2=5x=18 | | (7-2x)^2+1=0 | | 2(x+4)^2-18=14 | | 5(x^2-1)=3(x-1)(x+2) | | 1÷5+3÷4x=8÷9-6÷7x | | 4x=3-2 | | 8.2x-2.3x=106.2 | | 9/15=12x | | 5=-3x+85 | | P=66L10×w | | 2/3x-3=1/4x+7 | | (x-2)^2=1 | | 24m^2-23m-12=0 | | 5x+-45*9/20=14+5x |